Question

In a rectangle ABCD, AC and BD intersect at O . If angle BOC=40, find angle OBC and angle OCB

Answer 1

Step-by-step explanation:

in rectangle ABCD

Diagnals of rectangle are congruent bisects each other

AO=OC=OD=OB

In triangle BOC

mBOC=40

BO=OC

therefore triangle BOC is a isosceles triangle

OBC=OCB

measure of all angles of a triangle is 180°

BOC+OBC+OCB=180

40+2OBC=180

OBC =180-40/2

OBC = 70units

OCB=70 UNITS

Answer 2

Answer:in rectangle ABCD

Diagnals of rectangle are congruent bisects each other

AO=OC=OD=OB

In triangle BOC

mBOC=40

BO=OC

therefore triangle BOC is a isosceles triangle

OBC=OCB

measure of all angles of a triangle is 180°

BOC+OBC+OCB=180

40+2OBC=180

OBC =180-40/2

OBC = 70units

OCB=70 UNITS

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