In a rectangle ABCD, diagonals ACand BD intersect at O. If /CAB = 28°, find /DOC
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Answer: angle DOC is 124 degrees.
Explanation: we can say that angle Dca is also 28 degrees using the interior opposite angles theorem.
In a triangle, triangle doc, if two sides are equal then their corresponding angles are equal
In triangle doc, od is equal to oc as in a rectangle diagonals bisect each other.
So angle cdb is also 28 degrees like angle dca.
So angle doc is 180-28-28 = 124 degrees.
Hope it helps.... :)
Explanation: we can say that angle Dca is also 28 degrees using the interior opposite angles theorem.
In a triangle, triangle doc, if two sides are equal then their corresponding angles are equal
In triangle doc, od is equal to oc as in a rectangle diagonals bisect each other.
So angle cdb is also 28 degrees like angle dca.
So angle doc is 180-28-28 = 124 degrees.
Hope it helps.... :)
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