Question

In a rectangle ABCD,E is middle point of AD. If AD=40m and AB=48m . Then find EB

Answer 1

Here EB=52 m.

Step-by-step explanation:

Given:

In a rectangle ABCD,E is middle point of AD. If AD=40m and AB=48m .

Angle A=90°             (ALL ANGLES IN A RECTANGLE ARE RIGHT ANGLES)

Therefore according to Pythagoras theorem,

$EB^2 =AE^2+AB^2$                       (1)

$AE=\frac{1}{2}AD$                   (AD=40 m) (GIVEN)

$AE=\frac{1}{2} \times40$

AE=20 m

Also AB=48 m                 (GIVEN)

Therefore,

$EB^2 =AE^2+AB^2$                [from equation (1)]

$EB^2=20^2+48^2$

              = 400+2304

$EB^2=2704$

$EB=\sqrt{2704}$

Hence EB=52 m.

Answer 2

Answer:

hello

Step-by-step explanation:

EB=52 centimetre,,,,,,,,,,,,,,,