Question

in a rectangle ABCD on diagonal is inclined to one of its sides at 25 find angle AOB​

Answer 1

Answer:

In △BOC,  

∠OBC=∠OCB  ----- (Opposite angle of isosceles triangle)

∠OBC+∠OCB+∠BOC=180  ∘

 

25  ∘

+25  ∘

+∠BOC=180  ∘

 

Therefore, ∠BOC=130  ∘

     

So, ∠AOB+∠BOC=180  ∘

--------(Linear pair)

∠AOB=180  ∘

−130  ∘

 

∠AOB=50  ∘

 

So, the acute angle between the diagonal is 50  ∘