Question

In a rectangle ABCD, the diagonals intersect at 0.If angle AOB=62,then angle ODC is equal to:
plz answer fast​

Answer 1

$\huge\mathfrak\red{Here's\:Your\:Answer}$

So if an.AOB = 62°

Then an.DOC also = 62° {Opposite angles}

Now if DOB is a triangle , then we know that sum of all three sides is 180°

or DOC+ODC+OCD=180°

or 62°+ODC+OCD=180°

or ODC = 118°-OCD {Ans}

Answer 2

Answer:

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