Math, asked by anveshna, 29 days ago

in a rectangle ABCD the diagonals intersect at O correct the mistake in the following give reason
1) angleAOB=120°, angleABO=45°,angleOBC=45°
2)AO=6cm,BO=4.5cm,AB=7.5cm
3)AB=8cm,BC=6cm,AC=5.5cm
4)angleOAB=angleOAD=50°

if 2nd one not answer then ok
pls answer fast​

Answers

Answered by kiranbisht1674
3

Answer:

In a rectangle ABCD ,the diagonals intersect at O and

\textsf{AO=6cm ,BO=4.5cm,AB=7.5cm}AO=6cm ,BO=4.5cm,AB=7.5cm

\textbf{To find:}To find:

\textsf{The mistakes in the given data}The mistakes in the given data\begin{gathered}\boxed{\begin{minipage}{7cm}$\\\textsf{1.\;Diagonals of rectangle bisect each other}\\\\\textsf{2.\;Diagonals of rectangle are equal in length}$\end{minipage}}\end{gathered}

\implies\mathsf{OA=OC\;\;\&\;\;OB=OD}⟹OA=OC&OB=OD

\implies\mathsf{OA=OC=6\;\;\&\;\;OB=OD=4.5}⟹OA=OC=6&OB=OD=4.5

\mathsf{AC=OA+OC=6+6=12\;cm}AC=OA+OC=6+6=12cm

\mathsf{BD=OB+OD=4.5+4.5=9}BD=OB+OD=4.5+4.5=9

\mathsf{Length\;of\;AC\;{\neq}\;Length\;of\;BD}LengthofAC

=LengthofBD

\textsf{But, length of the diagonals should be equal}But, length of the diagonals should be equal

\mathsf{So\;it\;should\;be\;OA=OB}SoitshouldbeOA=OB

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