in a rectangle ABCD the diagonals intersect at O correct the mistake in the following give reason
1) angleAOB=120°, angleABO=45°,angleOBC=45°
2)AO=6cm,BO=4.5cm,AB=7.5cm
3)AB=8cm,BC=6cm,AC=5.5cm
4)angleOAB=angleOAD=50°
if 2nd one not answer then ok
pls answer fast
Answers
Answer:
In a rectangle ABCD ,the diagonals intersect at O and
\textsf{AO=6cm ,BO=4.5cm,AB=7.5cm}AO=6cm ,BO=4.5cm,AB=7.5cm
\textbf{To find:}To find:
\textsf{The mistakes in the given data}The mistakes in the given data\begin{gathered}\boxed{\begin{minipage}{7cm}$\\\textsf{1.\;Diagonals of rectangle bisect each other}\\\\\textsf{2.\;Diagonals of rectangle are equal in length}$\end{minipage}}\end{gathered}
\implies\mathsf{OA=OC\;\;\&\;\;OB=OD}⟹OA=OC&OB=OD
\implies\mathsf{OA=OC=6\;\;\&\;\;OB=OD=4.5}⟹OA=OC=6&OB=OD=4.5
\mathsf{AC=OA+OC=6+6=12\;cm}AC=OA+OC=6+6=12cm
\mathsf{BD=OB+OD=4.5+4.5=9}BD=OB+OD=4.5+4.5=9
\mathsf{Length\;of\;AC\;{\neq}\;Length\;of\;BD}LengthofAC
=LengthofBD
\textsf{But, length of the diagonals should be equal}But, length of the diagonals should be equal
\mathsf{So\;it\;should\;be\;OA=OB}SoitshouldbeOA=OB