Question

IN A RECTANGLE ABCD ,THE LENGTH OF DIAGONALS IS (AC=2x+4)AND (BD=3x+1 ). CALCULATE THE LENGTH OF TWICE OF IT'S DIAGONAL


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Answer 1

Answer:

3

⇒ In the given figure ABCD is a rectangle.

⇒ OA=2x+4 and OD=3x+1 [Given]

⇒ AC and BD are diagonals of a rectangle.

⇒ We know that diagonals of a rectangle are equal.

⇒ So, AC = BD

We can also write it as,

⇒ 2×OA=2×OD

⇒ 2×(2x+4) =2×(3x+1)

⇒ 2x+4=3x+1

∴ x=3

Step-by-step explanation:

hope it helps you dear

Answer 2

Answer:

Diagonal of rectangle is equal

2x + 4 = 3x + 1

x = 3

Diagonal = 10

THE LENGTH OF TWICE OF IT'S DIAGONAL :-

10 x 2 = 20

Step-by-step explanation:

Hope this help you