Math, asked by khushi7896, 5 months ago

in a rectangle abcd then diagonals intersects at 0 if angle aob = 62 degree , then angle doc = ?​

Answers

Answered by mannatdeepak
1

Answer:

In rectangle ABCD; diagonals are AC and BD.

AC and BD intersect at O.

So, angles AOB and COD are opposite angles.

So, angle AOB = angle COD = 62°.

Also, we know that diagonals of rectangle are equal in length and they bisect one another.

So, AC = BD and OC = OD.

So, triangle OCD is an isosceles triangle with OC = OD. Which means, angle OCD = angle ODC.

In triangle OCD, sum of three angles is 180°.

Angle ODC = (180° - 62°) / 2 = 59°.

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