Question

in a rectangle ABCD with BD as diagonal <DBC is equal to 80°.find the value of <ABD​

Answer 1

Answer:

Given in the rectangle ABCD ∠DAC=32°

⇒∠AOB=70°

⇒∠A=90°

⇒∠DAC+∠BAC=90°

⇒∠BAC=90°−32°=58°

From △AOB

⇒∠AOB+∠OAB+∠OBA=180° [ Sum of angle property ]

⇒58

o

+70

o

+∠OBA=180°

∴∠OBA=180°−58°−70°=52°

We know that ∠B=90°

⇒∠ABO+∠DBC=90°

⇒∠DBC=90°−52°=38°

Hence, the answer is 38°.

solution