Question

In a rectangle CALM ,CA =4cm and AL = 3cm. find the length of diagonals CL and AM

Answer 1

Hey there,

In the rectangle CALM 
since ∠CAL=∠ALM=∠LMC=∠MCA=90°
So we apply Pythagoras theorem on triangle CAL

We get,
CA²+AL²=CL²
4²+3²=CL²
Cl=√25=5 cm

Since the diagonals of a rectangle are equal, so CL=AM=5cm.

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Answer 2

Length of diagonals CL and AM are both equal to 5cm as follow:---

CALM is a rectangle we know that in a rectangle the opposide sides are equal in length and all angles are 90°.

So <CAL=<ALM=<<LMC=<MCA=90°

In rectangle CALM LC and MA are diagonals of rectangle .

Now CA=4cm and LA=3cm

In rectangle CAL is a right angled triangle at <A

So by pyathagoras we have

(CL)^2=(CA)^2+(AL)^2

(CL)^2=(4)^2+(3)^2

(CL)^2=16+9

(CL)^2=25

CL=5cm

The diagonals of rectangle are also equal so diagonals of rectangle CL and AM are both equal to 5cm.