In a rectangle if i reduce the length 5cm and increase the width 3cm then the area will be more than 9sq.cm or when i increse the length 3cm and width 2cm then the area will more than 67sq.cm.what is it's area????
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t length of rectangle = x units and Let breadth of rectangle = y units
Area =xy square units. According to given conditions,
xy – 9 = (x − 5) (y + 3)
⇒ xy – 9 = xy + 3x − 5y – 15
⇒ 3x − 5y = 6 … (1)
And, xy + 67 = (x + 3) (y + 2)
⇒ xy + 67 = xy + 2x + 3y + 6
⇒ 2x + 3y = 61 … (2)
From equation (1),
3x = 6 + 5y
⇒ x =
Putting this in (2), we get
2 + 3y = 61
⇒ 12 + 10y + 9y = 183
⇒ 19y = 171
⇒ y = 9 units
Putting value of y in (2), we get
2x + 3 (9) = 61
⇒ 2x = 61 – 27 = 34
⇒ x = 17 units
Therefore, length = 17 units and, breadth = 9 units
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