Question

In a rectangle KLMN and the diagonal AC and LN intersect at O. If KO= 4y+ 6 and ON= 3y + 11 , find the lengths of diagonals.

Answer 1

Answer

Here , the diagonal is half (ko and on)

So ,the diagonal km is twice of the ko

:4y+6=2(4y+6)=8y+12

Diagonal Ln is also twice of on

:3y+11=2(3y+11)=6y+22

Answer 2

Answer:

since diagonal half length is same

ko=on

simplifying that we will get y

substitute y in the equation will get KO

take double of ko will get diagonal length