Math, asked by nikitabehera5671, 3 months ago

In a rectangle lenght=3m+6 and breadth=3m. find the area and perimeter​

Answers

Answered by Ladylaurel
2

Answer ::

  • Area of rectangle = 9m² + 12m units
  • Perimeter of rectangle = 12m + 12 units

Step-by-step explanation ::

Formula used ::-

  • Area of rectangle = l × b
  • Perimeter = 2 ( l + b )

Where,

  • l = Length
  • b = Breadth

To Find :-

  • Area of rectangle
  • Perimeter of rectangle

Solution :-

Given that,

  • Length of rectangle = 3m + 6
  • Breadth = 3m

ACCORDING THE QUESTION,

The area of rectangle is,

As we know that,

 \dag \:  \:  \boxed{\green{\sf{Area \: of \: rectangle = l \times b}}}

Area = ( 3m + 6 ) ( 3m )

➟ 9m² + 12m

The area of rectangle is 9m² + 12m units.

Now, perimeter of rectangle is,

As we know that,

 \dag \:  \: \boxed{ \green{\sf{Perimeter \: of \: rectangle = 2(l+b)}}}

Perimeter = 2 ( 3m + 6 + 3m )

➟ ( 2 ) ( 6m + 6 )

➟ 12m + 12

The perimeter of rectangle is 12m + 12 units.

Answered by Anonymous
1

 \huge \sf \underline \red{Answer : }

\sf \underline \green{ \therefore \: Area \: of \: rectangle = 9 {m}^{2}  + 12m}

\sf \underline \green{ \therefore \: Perimeter\: of \: rectangle =  12m + 12}

 \huge \sf \underline \blue{To \:  find : }

  • Area and Perimeter of rectangle

  \huge\sf \underline \orange{solution: }

 \sf \underline{Given : }

  • length = 3m + 6

  • breadth = 3m

 \star \:  \sf \underline{Now \: we \: have \: to \: find \: area \: of \: rectangle : }

 \sf \underline{we \: know \: that : }

  \:  \:  \:  \:  \:  \: \sf{ \boxed{ \underline{ \underline{ \red{ \tt{Area \: of \: rectangle = l \times b \: }}}}}}

where

  • l is length (3m+6)

  • b is breadth (3m)

  \:  \:  \:  \:  \:  \:  \: \sf \implies{Area = (3m + 6)(3m)}

\:  \:  \:  \:  \:  \:  \: \sf \implies{ =  9 {m}^{2}  + 12m }

 \sf \underline \green{ \therefore \: Area \: of \: rectangle = 9 {m}^{2}  + 12m}

______________________________________

\star \:  \sf \underline{Now \: we \: have \: to \: find \: Perimeter \: of \: rectangle : }

\sf \underline{we \: know \: that : }

\:  \:  \:  \:  \:  \: \sf{ \boxed{ \underline{ \underline{ \red{ \tt{Perimeter\: of \: rectangle = 2(l + b) }}}}}}

 \:  \:  \:  \:  \:  \:  \: \sf \implies{Perimeter = 2(3m + 6 + 3)}

\:  \:  \:  \:  \:  \:  \: \sf \implies{ =  (2)(6m + 6) }

\:  \:  \:  \:  \:  \:  \: \sf \implies{ =  12m + 12 }

\sf \underline \green{ \therefore \: Perimeter\: of \: rectangle =  12m + 12}

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