Question

In a rectangle lenght=3m+6 and breadth=3m. find the area and perimeter​

Answer 1

Answer ::

• Area of rectangle = 9m² + 12m units
• Perimeter of rectangle = 12m + 12 units

Step-by-step explanation ::

Formula used ::-

• Area of rectangle = l × b
• Perimeter = 2 ( l + b )

Where,

• l = Length
• b = Breadth

To Find :-

• Area of rectangle
• Perimeter of rectangle

Solution :-

Given that,

• Length of rectangle = 3m + 6
• Breadth = 3m

ACCORDING THE QUESTION,

The area of rectangle is,

As we know that,

$\dag \: \: \boxed{\green{\sf{Area \: of \: rectangle = l \times b}}}$

➟ Area = ( 3m + 6 ) ( 3m )

➟ 9m² + 12m

The area of rectangle is 9m² + 12m units.

Now, perimeter of rectangle is,

As we know that,

$\dag \: \: \boxed{ \green{\sf{Perimeter \: of \: rectangle = 2(l+b)}}}$

➟ Perimeter = 2 ( 3m + 6 + 3m )

➟ ( 2 ) ( 6m + 6 )

➟ 12m + 12

The perimeter of rectangle is 12m + 12 units.

Answer 2

$\huge \sf \underline \red{Answer : }$

$\sf \underline \green{ \therefore \: Area \: of \: rectangle = 9 {m}^{2} + 12m}$

$\sf \underline \green{ \therefore \: Perimeter\: of \: rectangle = 12m + 12}$

$\huge \sf \underline \blue{To \: find : }$

• Area and Perimeter of rectangle

$\huge\sf \underline \orange{solution: }$

$\sf \underline{Given : }$

• length = 3m + 6

• breadth = 3m

$\star \: \sf \underline{Now \: we \: have \: to \: find \: area \: of \: rectangle : }$

$\sf \underline{we \: know \: that : }$

$\: \: \: \: \: \: \sf{ \boxed{ \underline{ \underline{ \red{ \tt{Area \: of \: rectangle = l \times b \: }}}}}}$

where

• l is length (3m+6)

• b is breadth (3m)

$\: \: \: \: \: \: \: \sf \implies{Area = (3m + 6)(3m)}$

$\: \: \: \: \: \: \: \sf \implies{ = 9 {m}^{2} + 12m }$

$\sf \underline \green{ \therefore \: Area \: of \: rectangle = 9 {m}^{2} + 12m}$

______________________________________

$\star \: \sf \underline{Now \: we \: have \: to \: find \: Perimeter \: of \: rectangle : }$

$\sf \underline{we \: know \: that : }$

$\: \: \: \: \: \: \sf{ \boxed{ \underline{ \underline{ \red{ \tt{Perimeter\: of \: rectangle = 2(l + b) }}}}}}$

$\: \: \: \: \: \: \: \sf \implies{Perimeter = 2(3m + 6 + 3)}$

$\: \: \: \: \: \: \: \sf \implies{ = (2)(6m + 6) }$

$\: \: \: \: \: \: \: \sf \implies{ = 12m + 12 }$

$\sf \underline \green{ \therefore \: Perimeter\: of \: rectangle = 12m + 12}$