Question

in a rectangle length=8cm,breadth=6cm then it's diagonal​

Answer 1

Step-by-step explanation:

Let ABCD is the rectangle whose AB =8 cm, BC=6cm,CD=8cm, and DA=6cm. E,F,G,H are the middle points of AB, BC, CD, and DA respectively. M,N,O,P,Q,R,S,T are the vertices of the regular octagon that formed ,and point M is on the line AE , other points N,O,P etc are on EB, BF, FC so on. Now MN=NO=OP=PQ=QR=RS=ST=TM= 2x .Then ME=x,

As AE=8/2= 4cm , AM=4-x

Similarly AT=3-x ,and TM=2x

As triangle ATM is a right triangle TM^2=AM^2+AT^2,

Or, (2x)^2=(4-x)^2+(3-x)^2

Or, 4x^2=16–8x+x^2+9–6x+x^2

Or, 2x^2+14x-25=0

Or,x=[-14±√{14^2–4×2×(-25)}]/(2×2)

Or, x={-14±√(196+200)}/4

Or, x=(-14±√396)/4

Or x=(-14±19.9)/4

Or x=5.9/4 …..Negative value discarded .

Or, x= 1.47 cm

So, ME =x=1.47 cm

MN=NO=…= 2x=2×1.47 = 2.94cm

Sides of the regular octagon is 2.94 cm

Answer 2

Answer:

Diagonal=10cm

Explanation is in the pic..

Mark me brain list if my answer is right....