in a Rectangle of perimeter 72m, length is 4m More than its Breadth....what is the sum of its's length and Breadth
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*Perimeter of a rectangle = 2(l+b)*
Given perimeter =72m
72m =2(l+b)
(l+b) =72/2
=l+b=36
HOPE YOU'LL UNDERSTAND THE SOLUTION
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