Question

In a rectangle of perimeter one meter, one side is five centimeters longer than the other. what are the lengths of the side? ​

Answer 1

Answer:

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Step-by-step explanation:

Let the breadth of rectangle be x.

So length will be x+5.

Perimeter of rectangle = 2(l+b)

                               100 = 2(x+x+5)

                               100 = 2(2x+5)

                               100 = 4x + 10

                        100 - 10 = 4x

                                90 = 4x

                                  $\frac{90}{4}$ = x

                         22.5cm = x

So length of rectangle = 22.5 + 5 = 27.5cm

So breadth of rectangle = 22.5cm

Answer 2

Given :

• perimeter a rectangle = 1 metre
• one side is five centimeters longer than the other

To find :

• Dimensions of rectangle

Formula used :

perimeter = sum of all sides

• perimeter of rectangle = 2(l+b)

where :-

• l = length
• b = breadth

Solution :

Let breadth be x cm

therefore length = (x+5) cm

Perimeter = 1 m

1 metre = 100 centimetres

therefore , Perimeter = 100 cm

Now , According to the question :-

⟹ 100 = 2 ( x+5+x)

⟹ 100/2 = ( x+5+x)

⟹ 50 = 2x+5

⟹ 50-5 = 2x

⟹ 45 = 2x

⟹ 45/2 = x

⟹ 22.5 = x

Breadth = 22.5 cm

length = 5+22.5 = 27.5 cm

Answer :

• length = 27.5 cm
• breadth = 22.5 cm

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Verification of answer :-

We can verify our answer by putting l = 27.5 cm and b= 22.5 cm in 2(l+b).

⟹ 2(l+b)

⟹ 2(27.5+ 22.5)

⟹ 2(50)

⟹ 2× 50

⟹ 100

Hence verified

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$\large\bf\blue{Additional-Information}$

Area of circle = πr²

Circumference of circle = 2πr

Area of square = (side)²

perimeter of square = 4× side

area of Rhombus = 1/2(diagonal 1)(diagonal 2)

Area of rectangle = length × breadth

Perimeter of rectangle = 2( length + breadth)

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