Question

In a rectangle the diagonals measure 4y-18 and 2y+2 .find the value of y and the length of the diagonal.

Answer 1

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$\large\mathcal\red{solution}$

the diagonals of a rectangle are same in length...

so

$4y - 18 = 2y + 2 \\ = > 4y - 2y = 2 + 18 \\ = > 2y = 20 \\ = >y = 10$

therefore the length of the diagonal is

=40-18=22

$\large\mathcal\red{hope\: this \: helps \:you......}$

Answer 2

Answer:

y=10

length of diagonals = 22

Step-by-step explanation:

Since diagonals of a rectangle are congruent,

4y-18=2y+2

4y-2y = 2+18

2y= 20

y= 20/2

y=10.

substituting the value of y, we get the length of diagonals as:

2y+2

=2(10) + 2

=20+2

=22