Question

In a rectangle the length and width measure respectively (3x - 1) and (2x + 3). Find the area of the rectangle if the perimeter is 54 cm. 40 points fast please

Answer 1

Answer:

182 square cm

Step-by-step explanation:

$Perimeter of a rectangle = 2(l + b) = 54 cm\\l = 3x - 1\\b = 2x + 3\\2(2x + 3 +3x - 1) = 54\\10x + 4 = 54\\10x = 50\\x = 5\\\\if x = 5\\l = 3(5) - 1 = 14 cm\\b = 2(5) + 3 = 13 cm\\\\ar(rectangle) = l x b = 14 x 13 = 182 cm^{2}$

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Answer 2

Answer:

Length of rectangle = (3x - 1) cm and

breadth of the rectangle = (2x + 3) cm

perimeter of the rectangle = 54 cm

2 ( L + B ) = 54

L+ B = 54/2

(3x - 1)+(2x + 3) = 27

3x-1+2x +3 =27

3x+2x +3-1 =27

5x +2 =27

5x  = 27-2

5x = 25

x= 25/5

x=5 cm

Now,

Length =3x - 1

           = 3 x 5 - 1

           = 15-1

           = 14 cm

Breadth =2x + 3

             = 2 x 5 + 3

             = 10+3

             = 13 cm

area of rectangle = L x B

                             = 14 X 13

                             = 182 $cm^{2}$

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