in a rectangle the length of one of its side is half the length of its adjacent side if its perimeter of rectangle is 43umits find its area. ans-102.7
Answers
Answer:
Let length of one side = L, then length of other side = L/2
Then perimeter = 2×(L + L/2) = 43
3L = 43
L = 43/3
Area of rectangle = L × L/2 = L^2/2
=(43/3)^2/2=102.7
Given:
In a rectangle, the length of one of its sides is half the length of its adjacent side.
The Perimeter of the rectangle = 43 units.
To Find:
The area of the rectangle.
Solution:
Let the length of one side of the rectangle be x.
So, According to the question,
The adjacent side will be x/2.
By the formula,
The perimeter of the rectangle = 2 × sum of both sides.
The perimeter of the rectangle = 2 × (x + x/2).
The perimeter of the rectangle = 2 × (2x +x) / 2.
The perimeter of the rectangle = 3x.
As given in the question,
The perimeter of the rectangle = 43 units.
so, 43 units = 3x.
x = 14.3 units.
Now, for the area,
The area of the rectangle = Product of both sides.
The area of the rectangle = x × x/2.
The area of the rectangle = x² / 2.
The area of the rectangle = (14.3)² / 2.
The area of the rectangle = 204.49 / 2.
The area of the rectangle = 102.7 unit square.
Hence, the area of the rectangle is 102.7 unit square.