Math, asked by harshiljpatel1110, 5 months ago

in a rectangle the length of one of its side is half the length of its adjacent side if its perimeter of rectangle is 43umits find its area. ans-102.7​

Answers

Answered by dkchakrabarty01
9

Answer:

Let length of one side = L, then length of other side = L/2

Then perimeter = 2×(L + L/2) = 43

3L = 43

L = 43/3

Area of rectangle = L × L/2 = L^2/2

=(43/3)^2/2=102.7

Answered by KailashHarjo
2

Given:

In a rectangle, the length of one of its sides is half the length of its adjacent side.

The Perimeter of the rectangle = 43 units.

To Find:

The area of the rectangle.

Solution:

Let the length of one side of the rectangle be x.

So, According to the question,

The adjacent side will be x/2.

By the formula,

The perimeter of the rectangle = 2 × sum of both sides.

The perimeter of the rectangle = 2 × (x + x/2).

The perimeter of the rectangle = 2 × (2x +x) / 2.

The perimeter of the rectangle = 3x.

As given in the question,

The perimeter of the rectangle = 43 units.

so, 43 units = 3x.

x = 14.3 units.

Now, for the area,

The area of the rectangle = Product of both sides.

The area of the rectangle = x × x/2.

The area of the rectangle = x² / 2.

The area of the rectangle = (14.3)² / 2.

The area of the rectangle = 204.49 / 2.

The area of the rectangle = 102.7 unit square.

Hence, the area of the rectangle is 102.7 unit square.

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