Question

in a rectangle the ratio of the length and width is 3:7.If it's perimeter is 50cm,find it's area​

Answer 1

Answer:

In a rectangle, the ratio of the length and width is 3:7. If it's perimeter is 50cm, then it's area is ​131.25 sq. cm.

Step-by-step explanation:

If the common multiple is x.

Then length = 3x and breadth = 7x

If perimeter is 50 cm

2 (length + breadth) = 50

2 (3x + 7x) = 50

2 (10x) = 50

20x = 50

x = 2.5

SO, length = 3(2.5) = 7.5 cm

And breadth of rectangle = 7(2.5) =17.5 cm

Area of rectangle = length ×breadth

= 7.5 × 17.5

= 131.25 sq. cm

Hence the area of rectangle is 131.25 sq. cm.

Answer 2

Answer:

the answer is

$131.25 {cm}^{2}$

Step-by-step explanation:

the ratio of length:width is 3:7

$</p><p>Perimeter is given as 50cm.</p><p>Applying the formula of perimeter and putting on the values,</p><p>[tex]Perimeter \: of rectangle = 2×(length + width) \\ 50 = 2 \times (3x + 7x) \\ 50 = 2 \times (10x) \\ 50 = 20x \\ \frac{50}{20} = x \\ 2.5 = x \\ x = 2.5$

putting the value of x in length and width

length = 3×2.5 = 7.5cm

width = 7×2.5 = 17.5cm

$Area \: of \: rectangle = length × width \\ = 7.5cm × 17.5cm \\ = 131.25 {cm}^{2}$