Physics, asked by paro9083, 1 year ago

In a rectangular element subjected to like principal tensile stresses p1 and p2 in two mutually perpendicular directions x and y, the naximum shear stress would occur along the

Answers

Answered by titu36
5

Answer:

engineering question uh

Answered by pawankumarb
0

Maximum shear Stress will be τ = \frac{p1-p2}{2} at  plane which is 45° from the principal stress p1.

Explanation:

Given that rectangular element is subjected to like principal tensile stresses p1 and p2 so,

According to the Maximum shear stress theory-

  • Maximum shear stress  τ = \frac{p1-p2}{2}
  • Plane at which maximum shear stress acts , lies 45° from the principal stress.

     

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