In a rectangular field of dimensions 500m*300m, a pond of dimensions 30m*20m*12m is dug out. the earth taken out is evenly spread on the remaining part on the field. what will be the increase in the level of the surface of the field?
Answers
Answered by
8
The volume of the pond = 30m*20m*12m
= 7200m^3
The area of upper surface of pond = 30m*20m = 600m^2
The area of rectangular field = 500m*300m = 150000 m^2
The area of remaining field after dug out = 150000m^2-600m^2
= 149400m^2
The increase length of surface = 7200m^3/149400m^2 =
= 7200m^3
The area of upper surface of pond = 30m*20m = 600m^2
The area of rectangular field = 500m*300m = 150000 m^2
The area of remaining field after dug out = 150000m^2-600m^2
= 149400m^2
The increase length of surface = 7200m^3/149400m^2 =
Similar questions