Math, asked by harigovindvk, 1 month ago

In a rectangular park of dimensions 50m*40m, a rectangular pond is constructed so that the area strip of uniform width surrounding the pond will be 1064m sq.. Find the length and breadth of the pond.
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Answers

Answered by Sanumarzi21
7

Answer⤵️⤵️

It is given that the dimensions of rectangular park is 50 m × 40 m.

∴ Area of the rectangular park = 50 × 40 = 2000 m2

Area of the grass surrounding the pond = 1184 m2

Now,

Area of the rectangular pond

= Area of the rectangular park − Area of the grass surrounding the rectangular pond

= 2000 − 1184

= 816 m2

Let the uniform width of the surrounding grass be x.

∴ Length of the rectangular pond = (50 − 2x) m

Breadth of the rectangular pond = (40 − 2x) m

Now,

Area of rectangular pond = 816 m2

∴ (50 − 2x) × (40 − 2x) = 816

⇒ 2000 − 80x − 100x + 4x2 = 816

⇒ 4x2 − 180x + 2000 − 816 = 0

⇒ 4x2 − 180x + 1184 = 0

⇒ x2 − 45x + 296 = 0

⇒ x2 − 37x − 8x + 296 = 0

⇒ x(x − 37) − 8(x − 37) = 0

⇒ (x − 8)(x − 37) = 0

⇒ x − 8 = 0 or x − 37 = 0

⇒ x = 8 or x = 37

For x = 37,

Length of rectangular pond = 50 − 2 × 37 = −24 m, which is not possible

So, x ≠ 37

Therefore, x = 8.

When x = 8,

Length of the rectangular pond = 50 − 2 × 8 = 50 − 16 = 34 m

Breadth of the rectangular pond = 40 − 2 × 8 = 40 − 16 = 24 m

Answered by Anonymous
3

Answer:

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