Question

In a regular hexagon ab+ac+ad+ea+fa=4ab prove

Answer 1

ya



for prove solve this

Answer 2

In a regular hexagon ab+ac+ad+ea+fa ≠ 4ab

Step-by-step explanation:

AB = BC = CD = DE = EF = AF = X

AC² = AB² + BC² - 2AB * BC Cos120°

=> AC² = X² + X² - 2X²(-1/2)

=> AC² = 3X²

=> AC = X√3

AD = 2X

AE = X√3

AF = X

AB + AC + AD + AE + AF  =  X  + X√3 + 2X + X√3 + X

= 4X + 2X√3

= X (4 + 2√3)

= AB(4 + 2√3) ≠ 4AB

Hence there is mistake in data in Question

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