Question

in a regular hexagon ABCDEF AB=P and BC =Q then find FA
1)P-Q
2) P+Q
3)p
4) Q​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Let the length of the side of the polygon be a.

As all sides are equal, length of AB = a

All the interior angles of regular hexagon are 120°

Distance between F and C  = a cos(60°) + a + a cos(60°) = 2a

FC is twice the magnitude of AB and is parallel to AB.

Therefore, FC = 2AB

By vector law of addition,

FA + AB + BC = FC

FA + AB + BC = 2AB

FA + P + Q  = 2P

FA  = 2P - P -Q

FA = P - Q

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