in a regular Pentagon,Abcde,draw diagonal BE and then find the measure of angle BAE , angle ABE, angle BED
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ABCDE is a Regular pentagon.
Sum of interior angles of a regular polygon: (N-2)×180°
here N= 5;so
(5-2)×180°=3×180=540°.
Since all the 5 angle of a regular pentagon are equal measure, each angle is
540/5 =108°.
So ∠ BAE = 108°.
In ΔABE,AB=AE
∠BAE+∠AEB+∠ABE=180°
108 +2∠ABE=180
∠ABE=36°.
now ∠BED =180-108=72°.
Sum of interior angles of a regular polygon: (N-2)×180°
here N= 5;so
(5-2)×180°=3×180=540°.
Since all the 5 angle of a regular pentagon are equal measure, each angle is
540/5 =108°.
So ∠ BAE = 108°.
In ΔABE,AB=AE
∠BAE+∠AEB+∠ABE=180°
108 +2∠ABE=180
∠ABE=36°.
now ∠BED =180-108=72°.
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