In a regular pentagon ABCDE prove that AC = BE.
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given:ABCDE is a regular pentagon
to show:AC=BE
In ∆ABC and ∆ABE
AB=AB(common)
angle ABC=angle BAE( interior angle)
BC=AE(side of regular pentagon)
∆ABC congruent to∆BAE( by SAS )
AC=BE(by CPCT)
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