Math, asked by cksajeev42, 5 months ago

in a regular polygon, one of its inner angles is 3times of outer angle
a. what is the sum of
inner angles and outer angle
b. how many sides are there for this polygon​

Answers

Answered by Anonymous
5

Answer:

8

Step-by-step explanation:

The sum of interior angles of a regular polygon is three the sum of its exterior angles.

Sum of all interior angles of a regular polygon = 180°

(n−2) where n = number of sides of polygon

Sum of all exterior angle of a regular polygon = 360°

According to question,

180°

(n−2)=3×360°

=>(n−2)=6

=>n=8

Number of sides of the polygon = 8

Mark as BRAINLIEST ✌️

Answered by Anonymous
11

Answer:

There are 8 sides to the figure.

The sum of exterior angles of any figure is 360. It does not matter how many sides it contains. It is always 360.

The sum of the interior angles of any figure is 180(n-2) where n = number of sides.

The equation would be 180(n-2) = 3*360.

Instead of multiplying the right side out, just divide both sides by 180. You get (n-2) = 3*2 so n-2=6 and n=8.

\color{purple}{HOPE} \color{purple}{THIS} \color{purple}{WILL} \color{purple}{HELPS} \color{purple}{YOU}

Similar questions