Math, asked by justinniji1234, 7 months ago

in a regular polygon the inner angle is 3 times of its outer angle angle (take outer angles xx) (a) what is the measure of an outer angle (b) find inner angle (c) find number of sides (d) find sum of inner and outer angles​

Answers

Answered by rajunaga110
0

Answer:

if outer angle is x then inner angle is 3x

so interior angle + exterior angle =180

x+3x=180

4x=180

x=180/4

x=45

so exterior angle is 4

2)and interior angle is =135

3) the number of sides= 360/exterior angle

=360/45=8

4) the sum of interior angles (n-2)*180

=(8-2)*180=1080

and total of exterior angles is 360

so sum of both = 1080+360=1440

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