in a regular polygon the inner angle is 3 times of its outer angle angle (take outer angles xx) (a) what is the measure of an outer angle (b) find inner angle (c) find number of sides (d) find sum of inner and outer angles
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if outer angle is x then inner angle is 3x
so interior angle + exterior angle =180
x+3x=180
4x=180
x=180/4
x=45
so exterior angle is 4
2)and interior angle is =135
3) the number of sides= 360/exterior angle
=360/45=8
4) the sum of interior angles (n-2)*180
=(8-2)*180=1080
and total of exterior angles is 360
so sum of both = 1080+360=1440
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