Question

In a relation , where b, c, S are physical quantities, b is and c is then the percentage error in S is

Answer 1

Given that,

The relation is

$S=\dfrac{b}{b-c}$

Suppose, $b=(5.0\pm 0.1)\ N$ and $c=(2.0\pm 0.2)\ N$

We need to calculate the percentage error in S

Using given equation

$S=\dfrac{b}{b-c}$

$S=b(b-c)^{-1}$

$S=1-bc^{-1}$

$S=1-\dfrac{b}{c}$

$\dfrac{\Delta S}{S}\times100=(\dfrac{\Delta b}{b}+\dfrac{\Delta c}{c})\times100$

Put the value into the formula

$\dfrac{\Delta S}{S}\times100=(\dfrac{0.1}{5.0}+\dfrac{0.2}{2.0})\times100$

$\dfrac{\Delta S}{S}=12\%$

Hence, The percentage error in S is 12%.

Learn more :

Topic : percentage error

https://brainly.in/question/18288351