Question

In a resonance tube with tuning fork of frequency 512 hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound is

Answer 1

Answer:

we have got two equations here:

1st eq. is-

l1 + e = v/4f.........(1)

2nd eq.is

l2 + e = 3v/4f........(2)

Apply (2) – (1)

l2 - l1 = 3v/4f – v/4f = 2v/4f = v/2f

delta(l2 - l1) / (l2 - l1) = delta(v) / v

delta(v) = 2f delta(l2 - l1) = 2f(deltal1 + deltal2) …......for maximum error

delta(v) = 2 x 512 x (0.1 + 0.1) = 2 x 512 x 0.2

delta(v) = 204.8 cm/s