Math, asked by nihan5363, 9 months ago

In a restaurant, Anil left tip Rs.75 which was 15% of his total bill. How much was his total bill? First answer will be marked brainleist

Answers

Answered by warylucknow
2

Answer:

Anil's total bill was of Rs. 500.

Step-by-step explanation:

Let the total bill amount be, Rs. x.

The tip added was of Rs. 75.

The amount of tip was 15% of the total bill amount.

That is, 15\%\ of\ x=75.

Solve this expression for x as follows:

15\%\ of\ x=75\\\frac{15}{100}\times x=75\\x=\frac{75\times100}{15}\\x=500

Thus, Anil's total bill was of Rs. 500.

Answered by Anonymous
6

Question:

In a restaurant, Anil left tip Rs.75 which was 15% of his total bill. How much was his total bill?

Answer:

His total bill was Rs. 500.

Given:

In a restaurant, Anil left tip Rs. 75.

Rs. 75 was 15%  of his original bill.

To find:

The original bill of Anil.

Explanation:

Let, Anil's original bill was, 'n'.

∴ He paid extra = (n×15/100)

                          =\dfrac{3n}{20} [∵ Dividing 15 and 100 by 5.]

According to the problem:

\dfrac{3n}{20}= 75

⇒ 3n = (75×20)

⇒ 3n = 1500

⇒ n = (1500÷3)

⇒ n = Rs. 500

∴ His total bill was Rs. 500.

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