Question

in a rhombus 1 diagonal is of 48cm another diagonal is 20 cm then find out its perimeter

Answer 1

=1/2×d1×d2
=1/2×48×20
=480
perimeter is 480

Answer 2

Answer:

Step-by-step explanation:

Let ABCD be a rhombus and the point of intersection of diagonal be O

we know that the diagonals of the rhombus bisects each other at right angle

So side OC=10 cm and side OB=24

and angle BOC =90

By pythagorus theorem

Side BC^2=(10)^2+(24)^2

Side BC^2=100+576

Side BC^2=676

Side BC=26

And we know that rhombus has its all side equal

Perimeter=26×4

Perimeter=104