Math, asked by safewaterheater, 9 months ago

In a rhombus ABCD, AB^C = 64*. Calculate:
a) BC^D. b) AD^B. c) BA^C
The best solution will be marked as brainliest...

Answers

Answered by TħeRøмαи
1

Answer:

I think ur question has some mistakes...

Step-by-step explanation:

Solution for other question acc. to me is below....

In a rhombus ABCD, angle ABC = 64 degrees. calculate angle BCD, angle ADB and angle BAC.

The information that is most helpful is

1. Opposite angles are congruent because a rhombus is a parallelogram, not necessarily because all sides are equal.

2. Adjacent angles are supplementary

3. The diagonals of a rhombus bisect the angles because the sides are all congruent as they are in a square.

Therefore angle BCD=180-64=116 degrees, angle ADB=(1/2)64=32 degrees, and angle BAC=(1/2)116=58 degrees.

Answered by shivjal
0

Answer:

In a rhombus ABCD, angle ABC = 64 degrees. calculate angle BCD, angle ADB and angle BAC.

The information that is most helpful is

1. Opposite angles are congruent because a rhombus is a parallelogram, not necessarily because all sides are equal.

2. Adjacent angles are supplementary

3. The diagonals of a rhombus bisect the angles because the sides are all congruent as they are in a square.

Therefore angle BCD=180-64=116 degrees, angle ADB=(1/2)64=32 degrees, and angle BAC=(1/2)116=58 degrees.

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