Question

In a rhombus ABCD, angle AOB equal 7z plus 6 and angle dao equal 5z plus 1.find angle cdo and dcb.

Answer 1

angle DCB is =angle dab therefore
angle DCB is 5z+1

DCB is 7z +6

Answer 2

Answer:

Angle aob= 90=7z+6

=> 7z=90-6

=>z=84/7=12

Putting the value of z in angle dao

=5z+1=5*12+1=60+1=61

Diagonal of rhombus bisects interior angle.... <dao=<bao=61

<dao+<bao=<A=61+61=122

Four angles of a rhombus are equal

Hence Angle DCB = 122

This is the right answer...