In a rhombus ABCD, ∠CBA=40°.Find the other angles
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Given ABCD is a Rhombus:
∠CBA=40° (Given)
∠ADC =40° (Diagonally opposite angles are equal )
∠DAB =180 - 40° = 140° (Opposite angles of a rhombus are supplementary)
∠BCD =140° (Diagonally opposite angles are equal )
Answer: The other 3 angles are 40°, 140° and 140°
Answered by
15
hey mate here's ur ans ↓↓
※※※※※※※※※※※※※※※
∵∠ CBA = 40°
∴ ∠ ADC = 40°(vertically opposite angle)
Again, ∠ DAB = 180° - 40° = 140°(opposite angles of a rhombus are supplementary.
∠ DCB = 140°( V.O.A)
※※※※※※※※※※※※※※※
hope it helps u☺☺✌
※※※※※※※※※※※※※※※
∵∠ CBA = 40°
∴ ∠ ADC = 40°(vertically opposite angle)
Again, ∠ DAB = 180° - 40° = 140°(opposite angles of a rhombus are supplementary.
∠ DCB = 140°( V.O.A)
※※※※※※※※※※※※※※※
hope it helps u☺☺✌
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