Question

In a rhombus ABCD, diagonal AC = 6 cm and diagonal BD = 8 cm. Find perimeter of
rhombus ABCD.
​

Answer 1

Answer:

20cm

Step-by-step explanation:

From pithagoras law...

side=

$\sqrt{3 {}^{2} + 4 {}^{2} } = 5$

Perimeter of rhombus 4*5 = 20cm

Answer 2

Answer:

Step-by-step explanation:

Given

AC=6cm

BD=8cm

To prove

Perimeter of rhombus ABCD

Proof

Perimeter of rhombus =1/2 (d1 ×d2)

1/2(6×8)cm

1/2(48)cm

12cm