Question

In a rhombus ABCD diagonals bisect each other at O and /_ AOB=(7z+6) ° then z=?​

Answer 1

Answer:

12°.

Step-by-step explanation:

Property:

Diagonals of a Rhombus bisect each other at right angles.

Here,

/_ AOB = 90° [By the above given property].

That is,

(7z + 6)° = 90°.

7z = 90° - 6° = 84°.

z = 84°/7 = 12°.

Therefore,

z = 12°.

Answer 2

Answer:

z=84/7=12°

Hope this helps mate