Question

In a rhombus ABCD,diagonals intersect each other at point P then find mtraingle APB=?​

Answer 1

90

Step-by-step explanation:

ABCD is a rhombus.

AC and BD are diagonals of rhombus.

We know that, diagonals of a rhombus bisect each other perpendicularly .

∴ AC⊥BD

i.e.AO⊥BO

∴ ∠AOB=90

Answer 2

Answer:

Step-by-step explanation:

Given: ABCD is a rhombus. diognal

meet ATO

Diagonals of a rhombus bisect each other

at right angles

Hence, in A OAB

OA2+OB2=AB2..(1)

In A OBC

OB2+OC2-BC2..(2)

Adding I and II, OA2+OC2= AB2+BC2-20BZ

OA2+OC2=2AD2-2 (4BD2) (since, ABCD

is a rhombus, sides are equal and diagonal bisect each other)

OA2+OC2=2AD2-2BD2