Question

In a rhombus ABCD,diagonals intersect each other at point P then find mtraingle APB=?​

Answer 1

Answer:

in a Rhombus the diagonals intersect each other at 90°

So m<APB = 90°

Answer 2

Answer:

In a rhombus ABCD, diagonals intersect each other at point P, then the ∠APB is equal to 90°.

Rhombus:

• Rhombus can be defined as a quadrilateral with all four sides having the same length.
• The opposite sides are parallel.
• The square is a special case of rhombus where all the four angles are 90°.

Step-by-step explanation:

It is given that ABCD is a rhombus whose diagonals intersect each other at a point P.

Hence, diagonals AC and BD intersect at point P.

We know that the diagonals of a rhombus intersect each other perpendicularly. That is, AC⊥BD

i.e., AP⊥BP

Therefore, ∠APB = 90°

Therefore, in a rhombus ABCD, the angle ∠APB is 90°.

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