Question

In a rhombus ABCD, diagonals intersect each other at point P then find m angle APB =?

Answer 1

Given :- In a rhombus ABCD, diagonals intersect each other at point P ?

To Find :- angle APB = ?

Answer :- 90° .

Explanation :-

we know that,

• Diagonals of a rhombus bisect each other at 90° .

therefore,

→ ∠APB = ∠APD = ∠BPC = ∠CPD = 90° .

Hence, we can conclude that, angle APB is equal to 90° .

Extra knowledge :-

Properties of Rhombus :-

• All sides are equal in measure .
• Opposite angles are equal .
• Diagonals bisects opposite angles .
• Since opposite sides are parallel, adjacent angles are supplementry .
• Area of Rhombus = (1/2) * Diagonal 1 * Diagonal 2 = Side * Height .

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