Question

in a rhombus ABCD , diagonals intersect each other at point P then find measure angle APB

The diagnols of rhombus bisect each other at 90°

therefore : angle APB is 90°
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Answer 1

Answer:

90°

Step-by-step explanation:

We know that,

Diagonals of a rhombus bisect each other at 90° .

therefore,

→ ∠APB = ∠APD = ∠BPC = ∠CPD = 90° .

Hence, we can conclude that, angle APB is equal to 90° .