in a rhombus ABCD, digoninals intersect each other at point p then find m <APB=
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To Find :- angle APB = ?
Answer :- 90° .
Explanation :-
we know that,
Diagonals of a rhombus bisect each other at 90° .
therefore,
→ ∠APB = ∠APD = ∠BPC = ∠CPD = 90° .
Hence, we can conclude that, angle APB is equal to 90° .
Extra knowledge :-
Properties of Rhombus :-
All sides are equal in measure .
Opposite angles are equal .
Diagonals bisects opposite angles .
Since opposite sides are parallel, adjacent angles are supplementry .
Area of Rhombus = (1/2) * Diagonal 1 * Diagonal 2 = Side * Height .
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