in a rhombus ABCD ,if AB=10cm BD=16cm find the diagonal AC
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Step-by-step explanation:
AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.
From Pithagoras's rule
AO=√(AB^2-BO^2)
=√(100-64)
=√36
=6.
And we know AC=2AO
=2*6=12cm
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