Question

in a rhombus ABCD ,if AB=10cm BD=16cm find the diagonal AC​

Answer 1

Answer:

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Step-by-step explanation:

AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.

From Pithagoras's rule

AO=√(AB^2-BO^2)

=√(100-64)

=√36

=6.

And we know AC=2AO

=2*6=12cm