In a rhombus ABCD . if AB = BD then find angle ADC
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since ABCD is a Rhombus then
AB=BC=CD=DA
but from the question AC=AB
therefore, AC=BC also
I.e.AB=BC=AC
I.e ABC is isosceles triangle
therefore <ABC=<BCD=<BAC=60°
and in the same way <D=<DAC=<ACD=60°
then <A=<C=120°(by adding the adjoining angle)
and <B=<D=60°
AB=BC=CD=DA
but from the question AC=AB
therefore, AC=BC also
I.e.AB=BC=AC
I.e ABC is isosceles triangle
therefore <ABC=<BCD=<BAC=60°
and in the same way <D=<DAC=<ACD=60°
then <A=<C=120°(by adding the adjoining angle)
and <B=<D=60°
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