in a rhombus Abcd if bc=8x-10 and cd=3x+10 find the side of rhombus
Answers
Answer:
Correct option is D)
Let the coordinate of A be (0,α).
Since the sides AB and AD are parallel to the lines y=x+2 and y=7x+3 respectively.
Therefore the diagonal AC is parallel to the bisector of the angle between these two lines.
The equation of the bisectors are given by,
2
x−y+2
=±
50
7x−y+3
⇒5(x−y+2)=±(7x−y+3)
⇒2x+4y−7=0 and 12x−6y+13=0
Thus, the diagonals of the rhombus are parallel to the lines
2x+4y−7=0 and 12x−6y+14=0
Therefore slope of AE=−
4
2
or
6
12
⇒
1−0
2−α
=−
2
1
or
1−0
2−α
=2
a = 5/2 or a = 0.... Ans
Answer:
Step-by-step explanation:
We know , In rhombus all sides are equal
so,
BC = CD
8x - 10 = 3x + 10
8x - 3x = 10+10
5x = 20
x = 20/5
x = 4
________________________________________________
BC = 8x-10
= 8x4 - 10
= 32 - 10
= 22
CD =3x+10
= 3x4+10
= 12 +10
= 22
BC = CD = 22