Question

in a rhombus Abcd if bc=8x-10 and cd=3x+10 find the side of rhombus

Answer 1

Answer:

Step-by-step explanation:

We know , In rhombus all sides are equal

so,

BC = CD

8x - 10 = 3x + 10

8x - 3x  = 10+10

5x = 20

x = 20/5

x = 4

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BC = 8x-10

    = 8x4 - 10

    = 32 - 10

     =  22

CD =3x+10

    = 3x4+10

    = 12 +10

    = 22

BC = CD = 22