In a rhombus ABCD if BC=8x-10 and CD=3x+10 find the sides of rhombus
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Answer:
Correct option is D)
Let the coordinate of A be (0,α).
Since the sides AB and AD are parallel to the lines y=x+2 and y=7x+3 respectively.
Therefore the diagonal AC is parallel to the bisector of the angle between these two lines.
The equation of the bisectors are given by,
2
x−y+2
=±
50
7x−y+3
⇒5(x−y+2)=±(7x−y+3)
⇒2x+4y−7=0 and 12x−6y+13=0
Thus, the diagonals of the rhombus are parallel to the lines
2x+4y−7=0 and 12x−6y+14=0
Therefore slope of AE=−
4
2
or
6
12
⇒
1−0
2−α
=−
2
1
or
1−0
2−α
=2
⇒α=
2
5
or α=0
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