Question

in a rhombus ABCD , measure of diagonals AC and BC are 6 and 8 respectively. Find BC

Answer 1

actually diagonals are AC and BD.
since we know that diagonal bisects each other
so half length will be 3 and 4 respectively, 
By applying Pythagoras' theorem 
BC=√(3²+ 4²)
=√25
=5

Answer 2

Diagonal should be ac and bd And we know that diagonal bisect each other Let the point where they cut be o So... AO=3 and BD=4 Now using pythoghoras We get BC=(3^2+4^2)^1/2 Bc=5