In a rhombus ABCD , O is any interior point such that OA=OC , then prove that D, O and B are collinear.
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D, O, and B are collinear .
GIVEN
ABCD is a rhombus.
O is any interior point such that OA=OC.
TO FIND
D, O and B are collinear.
SOLUTION
We can simply solve the above problem as follows;
In ΔCOB and ΔAOB
OA = OC (given)
AB = BC (Side of a rhombus)
OB = OB (Common side)
By S-S-S congruency;
ΔAOB ≈ ΔCOB
Therefore,
∠AOB = ∠COB (i)
Similarly,
ΔAOD ≈ ΔCOD
∠AOB = ∠BOC (ii)
∠AOB + ∠BOC + ∠COD + ∠AOD = 360°
From (i) and (ii)
∠BOC + ∠BOC + ∠COD + ∠COD = 360°
2∠BOC + 2∠COD = 360°
∠BOC + ∠COD = 360/2 = 180°
∠BOC + ∠COD = ∠DOB
Therefore,
∠DOB = 180°
Therefore, D, O, and B are collinear .
*Picture for refernce.
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